3.1.11 \(\int \frac {x^2 (d+e x^3)}{a+b x^3+c x^6} \, dx\)

Optimal. Leaf size=72 \[ \frac {e \log \left (a+b x^3+c x^6\right )}{6 c}-\frac {(2 c d-b e) \tanh ^{-1}\left (\frac {b+2 c x^3}{\sqrt {b^2-4 a c}}\right )}{3 c \sqrt {b^2-4 a c}} \]

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Rubi [A]  time = 0.07, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {1468, 634, 618, 206, 628} \begin {gather*} \frac {e \log \left (a+b x^3+c x^6\right )}{6 c}-\frac {(2 c d-b e) \tanh ^{-1}\left (\frac {b+2 c x^3}{\sqrt {b^2-4 a c}}\right )}{3 c \sqrt {b^2-4 a c}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^2*(d + e*x^3))/(a + b*x^3 + c*x^6),x]

[Out]

-((2*c*d - b*e)*ArcTanh[(b + 2*c*x^3)/Sqrt[b^2 - 4*a*c]])/(3*c*Sqrt[b^2 - 4*a*c]) + (e*Log[a + b*x^3 + c*x^6])
/(6*c)

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 634

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rule 1468

Int[(x_)^(m_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.)*((d_) + (e_.)*(x_)^(n_))^(q_.), x_Symbol] :>
Dist[1/n, Subst[Int[(d + e*x)^q*(a + b*x + c*x^2)^p, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x]
&& EqQ[n2, 2*n] && EqQ[Simplify[m - n + 1], 0]

Rubi steps

\begin {align*} \int \frac {x^2 \left (d+e x^3\right )}{a+b x^3+c x^6} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {d+e x}{a+b x+c x^2} \, dx,x,x^3\right )\\ &=\frac {e \operatorname {Subst}\left (\int \frac {b+2 c x}{a+b x+c x^2} \, dx,x,x^3\right )}{6 c}+\frac {(2 c d-b e) \operatorname {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,x^3\right )}{6 c}\\ &=\frac {e \log \left (a+b x^3+c x^6\right )}{6 c}-\frac {(2 c d-b e) \operatorname {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x^3\right )}{3 c}\\ &=-\frac {(2 c d-b e) \tanh ^{-1}\left (\frac {b+2 c x^3}{\sqrt {b^2-4 a c}}\right )}{3 c \sqrt {b^2-4 a c}}+\frac {e \log \left (a+b x^3+c x^6\right )}{6 c}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 71, normalized size = 0.99 \begin {gather*} \frac {e \log \left (a+b x^3+c x^6\right )-\frac {2 (b e-2 c d) \tan ^{-1}\left (\frac {b+2 c x^3}{\sqrt {4 a c-b^2}}\right )}{\sqrt {4 a c-b^2}}}{6 c} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^2*(d + e*x^3))/(a + b*x^3 + c*x^6),x]

[Out]

((-2*(-2*c*d + b*e)*ArcTan[(b + 2*c*x^3)/Sqrt[-b^2 + 4*a*c]])/Sqrt[-b^2 + 4*a*c] + e*Log[a + b*x^3 + c*x^6])/(
6*c)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^2 \left (d+e x^3\right )}{a+b x^3+c x^6} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(x^2*(d + e*x^3))/(a + b*x^3 + c*x^6),x]

[Out]

IntegrateAlgebraic[(x^2*(d + e*x^3))/(a + b*x^3 + c*x^6), x]

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fricas [A]  time = 1.28, size = 216, normalized size = 3.00 \begin {gather*} \left [\frac {{\left (b^{2} - 4 \, a c\right )} e \log \left (c x^{6} + b x^{3} + a\right ) - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c d - b e\right )} \log \left (\frac {2 \, c^{2} x^{6} + 2 \, b c x^{3} + b^{2} - 2 \, a c + {\left (2 \, c x^{3} + b\right )} \sqrt {b^{2} - 4 \, a c}}{c x^{6} + b x^{3} + a}\right )}{6 \, {\left (b^{2} c - 4 \, a c^{2}\right )}}, \frac {{\left (b^{2} - 4 \, a c\right )} e \log \left (c x^{6} + b x^{3} + a\right ) - 2 \, \sqrt {-b^{2} + 4 \, a c} {\left (2 \, c d - b e\right )} \arctan \left (-\frac {{\left (2 \, c x^{3} + b\right )} \sqrt {-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right )}{6 \, {\left (b^{2} c - 4 \, a c^{2}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^3+d)/(c*x^6+b*x^3+a),x, algorithm="fricas")

[Out]

[1/6*((b^2 - 4*a*c)*e*log(c*x^6 + b*x^3 + a) - sqrt(b^2 - 4*a*c)*(2*c*d - b*e)*log((2*c^2*x^6 + 2*b*c*x^3 + b^
2 - 2*a*c + (2*c*x^3 + b)*sqrt(b^2 - 4*a*c))/(c*x^6 + b*x^3 + a)))/(b^2*c - 4*a*c^2), 1/6*((b^2 - 4*a*c)*e*log
(c*x^6 + b*x^3 + a) - 2*sqrt(-b^2 + 4*a*c)*(2*c*d - b*e)*arctan(-(2*c*x^3 + b)*sqrt(-b^2 + 4*a*c)/(b^2 - 4*a*c
)))/(b^2*c - 4*a*c^2)]

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giac [A]  time = 1.21, size = 70, normalized size = 0.97 \begin {gather*} \frac {e \log \left (c x^{6} + b x^{3} + a\right )}{6 \, c} + \frac {{\left (2 \, c d - b e\right )} \arctan \left (\frac {2 \, c x^{3} + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{3 \, \sqrt {-b^{2} + 4 \, a c} c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^3+d)/(c*x^6+b*x^3+a),x, algorithm="giac")

[Out]

1/6*e*log(c*x^6 + b*x^3 + a)/c + 1/3*(2*c*d - b*e)*arctan((2*c*x^3 + b)/sqrt(-b^2 + 4*a*c))/(sqrt(-b^2 + 4*a*c
)*c)

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maple [A]  time = 0.00, size = 99, normalized size = 1.38 \begin {gather*} -\frac {b e \arctan \left (\frac {2 c \,x^{3}+b}{\sqrt {4 a c -b^{2}}}\right )}{3 \sqrt {4 a c -b^{2}}\, c}+\frac {2 d \arctan \left (\frac {2 c \,x^{3}+b}{\sqrt {4 a c -b^{2}}}\right )}{3 \sqrt {4 a c -b^{2}}}+\frac {e \ln \left (c \,x^{6}+b \,x^{3}+a \right )}{6 c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(e*x^3+d)/(c*x^6+b*x^3+a),x)

[Out]

1/6*e*ln(c*x^6+b*x^3+a)/c+2/3/(4*a*c-b^2)^(1/2)*arctan((2*c*x^3+b)/(4*a*c-b^2)^(1/2))*d-1/3/(4*a*c-b^2)^(1/2)*
arctan((2*c*x^3+b)/(4*a*c-b^2)^(1/2))*e*b/c

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^3+d)/(c*x^6+b*x^3+a),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(4*a*c-b^2>0)', see `assume?` f
or more details)Is 4*a*c-b^2 positive or negative?

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mupad [B]  time = 2.63, size = 1632, normalized size = 22.67

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2*(d + e*x^3))/(a + b*x^3 + c*x^6),x)

[Out]

- (log(a + b*x^3 + c*x^6)*(3*b^2*e - 12*a*c*e))/(2*(36*a*c^2 - 9*b^2*c)) - (atan((b*(4*a*c - b^2)^(3/2)*(a*c*d
*e^2 - a*b*e^3 - ((3*b^2*e - 12*a*c*e)*(((3*b^2*e - 12*a*c*e)*(72*a*b*c^2*e - 36*a*c^3*d + (54*a*b*c^3*(3*b^2*
e - 12*a*c*e))/(36*a*c^2 - 9*b^2*c)))/(2*(36*a*c^2 - 9*b^2*c)) + 15*a*b*c*e^2 - 12*a*c^2*d*e))/(2*(36*a*c^2 -
9*b^2*c)) + ((((b*e - 2*c*d)*(72*a*b*c^2*e - 36*a*c^3*d + (54*a*b*c^3*(3*b^2*e - 12*a*c*e))/(36*a*c^2 - 9*b^2*
c)))/(6*c*(4*a*c - b^2)^(1/2)) + (9*a*b*c^2*(3*b^2*e - 12*a*c*e)*(b*e - 2*c*d))/((36*a*c^2 - 9*b^2*c)*(4*a*c -
b^2)^(1/2)))*(b*e - 2*c*d))/(6*c*(4*a*c - b^2)^(1/2)) + (3*a*b*c*(3*b^2*e - 12*a*c*e)*(b*e - 2*c*d)^2)/(2*(36
*a*c^2 - 9*b^2*c)*(4*a*c - b^2))))/(a^2*c*(b^3*e^3 - 8*c^3*d^3 + 12*b*c^2*d^2*e - 6*b^2*c*d*e^2)) - (4*x^3*((b
*(b^2*e^3 + c^2*d^2*e + ((3*b^2*e - 12*a*c*e)*(6*c^3*d^2 + ((3*b^2*e - 12*a*c*e)*(45*b^2*c^2*e - 36*b*c^3*d +
(27*b^2*c^3*(3*b^2*e - 12*a*c*e))/(36*a*c^2 - 9*b^2*c)))/(2*(36*a*c^2 - 9*b^2*c)) + 12*b^2*c*e^2 - 18*b*c^2*d*
e))/(2*(36*a*c^2 - 9*b^2*c)) - 2*b*c*d*e^2 - ((((b*e - 2*c*d)*(45*b^2*c^2*e - 36*b*c^3*d + (27*b^2*c^3*(3*b^2*
e - 12*a*c*e))/(36*a*c^2 - 9*b^2*c)))/(6*c*(4*a*c - b^2)^(1/2)) + (9*b^2*c^2*(3*b^2*e - 12*a*c*e)*(b*e - 2*c*d
))/(2*(36*a*c^2 - 9*b^2*c)*(4*a*c - b^2)^(1/2)))*(b*e - 2*c*d))/(6*c*(4*a*c - b^2)^(1/2)) - (3*b^2*c*(3*b^2*e
- 12*a*c*e)*(b*e - 2*c*d)^2)/(4*(36*a*c^2 - 9*b^2*c)*(4*a*c - b^2))))/(4*a^2*c) - ((2*a*c - b^2)*(((3*b^2*e -
12*a*c*e)*(((b*e - 2*c*d)*(45*b^2*c^2*e - 36*b*c^3*d + (27*b^2*c^3*(3*b^2*e - 12*a*c*e))/(36*a*c^2 - 9*b^2*c))
)/(6*c*(4*a*c - b^2)^(1/2)) + (9*b^2*c^2*(3*b^2*e - 12*a*c*e)*(b*e - 2*c*d))/(2*(36*a*c^2 - 9*b^2*c)*(4*a*c -
b^2)^(1/2))))/(2*(36*a*c^2 - 9*b^2*c)) - (b^2*(b*e - 2*c*d)^3)/(4*(4*a*c - b^2)^(3/2)) + ((b*e - 2*c*d)*(6*c^3
*d^2 + ((3*b^2*e - 12*a*c*e)*(45*b^2*c^2*e - 36*b*c^3*d + (27*b^2*c^3*(3*b^2*e - 12*a*c*e))/(36*a*c^2 - 9*b^2*
c)))/(2*(36*a*c^2 - 9*b^2*c)) + 12*b^2*c*e^2 - 18*b*c^2*d*e))/(6*c*(4*a*c - b^2)^(1/2))))/(4*a^2*c*(4*a*c - b^
2)^(1/2)))*(4*a*c - b^2)^(3/2))/(b^3*e^3 - 8*c^3*d^3 + 12*b*c^2*d^2*e - 6*b^2*c*d*e^2) + ((2*a*c - b^2)*(4*a*c
- b^2)*(((3*b^2*e - 12*a*c*e)*(((b*e - 2*c*d)*(72*a*b*c^2*e - 36*a*c^3*d + (54*a*b*c^3*(3*b^2*e - 12*a*c*e))/
(36*a*c^2 - 9*b^2*c)))/(6*c*(4*a*c - b^2)^(1/2)) + (9*a*b*c^2*(3*b^2*e - 12*a*c*e)*(b*e - 2*c*d))/((36*a*c^2 -
9*b^2*c)*(4*a*c - b^2)^(1/2))))/(2*(36*a*c^2 - 9*b^2*c)) + ((b*e - 2*c*d)*(((3*b^2*e - 12*a*c*e)*(72*a*b*c^2*
e - 36*a*c^3*d + (54*a*b*c^3*(3*b^2*e - 12*a*c*e))/(36*a*c^2 - 9*b^2*c)))/(2*(36*a*c^2 - 9*b^2*c)) + 15*a*b*c*
e^2 - 12*a*c^2*d*e))/(6*c*(4*a*c - b^2)^(1/2)) - (a*b*(b*e - 2*c*d)^3)/(2*(4*a*c - b^2)^(3/2))))/(a^2*c*(b^3*e
^3 - 8*c^3*d^3 + 12*b*c^2*d^2*e - 6*b^2*c*d*e^2)))*(b*e - 2*c*d))/(3*c*(4*a*c - b^2)^(1/2))

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sympy [B]  time = 6.55, size = 287, normalized size = 3.99 \begin {gather*} \left (\frac {e}{6 c} - \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) \log {\left (x^{3} + \frac {- 12 a c \left (\frac {e}{6 c} - \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) + 2 a e + 3 b^{2} \left (\frac {e}{6 c} - \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) - b d}{b e - 2 c d} \right )} + \left (\frac {e}{6 c} + \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) \log {\left (x^{3} + \frac {- 12 a c \left (\frac {e}{6 c} + \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) + 2 a e + 3 b^{2} \left (\frac {e}{6 c} + \frac {\sqrt {- 4 a c + b^{2}} \left (b e - 2 c d\right )}{6 c \left (4 a c - b^{2}\right )}\right ) - b d}{b e - 2 c d} \right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(e*x**3+d)/(c*x**6+b*x**3+a),x)

[Out]

(e/(6*c) - sqrt(-4*a*c + b**2)*(b*e - 2*c*d)/(6*c*(4*a*c - b**2)))*log(x**3 + (-12*a*c*(e/(6*c) - sqrt(-4*a*c
+ b**2)*(b*e - 2*c*d)/(6*c*(4*a*c - b**2))) + 2*a*e + 3*b**2*(e/(6*c) - sqrt(-4*a*c + b**2)*(b*e - 2*c*d)/(6*c
*(4*a*c - b**2))) - b*d)/(b*e - 2*c*d)) + (e/(6*c) + sqrt(-4*a*c + b**2)*(b*e - 2*c*d)/(6*c*(4*a*c - b**2)))*l
og(x**3 + (-12*a*c*(e/(6*c) + sqrt(-4*a*c + b**2)*(b*e - 2*c*d)/(6*c*(4*a*c - b**2))) + 2*a*e + 3*b**2*(e/(6*c
) + sqrt(-4*a*c + b**2)*(b*e - 2*c*d)/(6*c*(4*a*c - b**2))) - b*d)/(b*e - 2*c*d))

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